(x^2+2x+1)/(1-x)=1.03

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Solution for (x^2+2x+1)/(1-x)=1.03 equation: 


D( x )

1-x = 0

1-x = 0

1-x = 0

1-x = 0 // - 1

-x = -1 // * -1

x = 1

x in (-oo:1) U (1:+oo)

(x^2+2*x+1)/(1-x) = 1.03 // - 1.03

(x^2+2*x+1)/(1-x)-1.03 = 0

(x^2+2*x+1)/(1-x)+(-1.03*(1-x))/(1-x) = 0

x^2-1.03*(1-x)+2*x+1 = 0

x^2+3.03*x-0.03 = 0

x^2+3.03*x-0.03 = 0

x^2+3.03*x-0.03 = 0

DELTA = 3.03^2-(-0.03*1*4)

DELTA = 3.03^2+0.12

DELTA = 9.3009

DELTA > 0

x = ((3.03^2+0.12)^(1/2)-3.03)/(1*2) or x = (-(3.03^2+0.12)^(1/2)-3.03)/(1*2)

x = ((3.03^2+0.12)^(1/2)-3.03)/2 or x = (-((3.03^2+0.12)^(1/2)+3.03))/2

(x+((3.03^2+0.12)^(1/2)+3.03)/2)*(x-(((3.03^2+0.12)^(1/2)-3.03)/2)) = 0

((x+((3.03^2+0.12)^(1/2)+3.03)/2)*(x-(((3.03^2+0.12)^(1/2)-3.03)/2)))/(1-x) = 0

((x+((3.03^2+0.12)^(1/2)+3.03)/2)*(x-(((3.03^2+0.12)^(1/2)-3.03)/2)))/(1-x) = 0 // * 1-x

(x+((3.03^2+0.12)^(1/2)+3.03)/2)*(x-(((3.03^2+0.12)^(1/2)-3.03)/2)) = 0

( x+((3.03^2+0.12)^(1/2)+3.03)/2 )

x+((3.03^2+0.12)^(1/2)+3.03)/2 = 0 // - ((3.03^2+0.12)^(1/2)+3.03)/2

x = -(((3.03^2+0.12)^(1/2)+3.03)/2)

( x-(((3.03^2+0.12)^(1/2)-3.03)/2) )

x-(((3.03^2+0.12)^(1/2)-3.03)/2) = 0 // + ((3.03^2+0.12)^(1/2)-3.03)/2

x = ((3.03^2+0.12)^(1/2)-3.03)/2

x in { -(((3.03^2+0.12)^(1/2)+3.03)/2), ((3.03^2+0.12)^(1/2)-3.03)/2 }

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